# SOLUTION: 64 = 70 - .003H , solve for H. I started by moving H to the other side of equation, and putting underneath 64 , but what do I do with 64 ?

Algebra ->  Algebra  -> Inverses -> SOLUTION: 64 = 70 - .003H , solve for H. I started by moving H to the other side of equation, and putting underneath 64 , but what do I do with 64 ?       Log On

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 Algebra: Inverse operations for addition and multiplication, reciprocals Solvers Lessons Answers archive Quiz In Depth

 Click here to see ALL problems on Inverses Question 205797: 64 = 70 - .003H , solve for H. I started by moving H to the other side of equation, and putting underneath 64 , but what do I do with 64 ? Found 2 solutions by Targetweek, stanbon:Answer by Targetweek(62)   (Show Source): You can put this solution on YOUR website!Instead of moving H first combine like terms and then solve for H 1. 2. 3. 4. 5. Answer by stanbon(57223)   (Show Source): You can put this solution on YOUR website!64 = 70 - .003H , solve for H. 0.003H = 70 - 60 0.003H = 10 H = 333 1/3 ===================== Cheers, Stan H.