I'll change the numbers so you'll have to do something other than type them
in and get credit for what somebody else did.
You need 605 mL of a 75% alcohol solution. On hand, you have a 45%
alcohol mixture. How much of the 45% alcohol mixture and pure alcohol will
you need to obtain the desired solution?
|How many ml?|Strength| ml of pure alcohol
-------------------------------------------------
Solution| x | 0.45 | 0.45x
Alcohol | y | 1.00 | 1.00y
---------------------------------------------
605 0.75 0.75(605)
The equations come from the first and last columns:
x + y = 605
0.45x + 1.00y = 0.75(605)
--------------------------
Multiply the second equation through by 100,
that is, move the decimal 2 places right on one factor:
x + y = 605
45x + 100y = 75(605)
--------------------------
Multiply 75 times 605 get 45375
x + y = 605
45x + 100y = 45275
--------------------------
Solve the first equation for x
x = 605 - y
Substitute that for x in the second equation
45x + 100y = 45275
45(605 - y) + 100y = 45275
27225 - 45y + 100y = 45275
27226 + 55y = 45275
55y = 18150
y = 18150/55
y = 330 ml of pure alcohol
Substitute in
x = 605 - y
x = 605 - 330
x = 275 ml of mixture
Now do the same with your numbers.
Edwin