# SOLUTION: I'm returning back to school after 25yrs, need help with algerbra, really bad. my problem is from textbook "Prealgerbra" by Aufmann,Baker and Lockwood, chapter 7.5, question # 14.

Algebra ->  -> SOLUTION: I'm returning back to school after 25yrs, need help with algerbra, really bad. my problem is from textbook "Prealgerbra" by Aufmann,Baker and Lockwood, chapter 7.5, question # 14.      Log On

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 Question 44642This question is from textbook prealgebra : I'm returning back to school after 25yrs, need help with algerbra, really bad. my problem is from textbook "Prealgerbra" by Aufmann,Baker and Lockwood, chapter 7.5, question # 14. PROBLEM: The distance (d) a spring will stretch varies directly as the force (f) applied to the spring. If a force of 12lb is required to stretch a spring 3inchs, what force is required to stretch the spring 5 inches? this probable seem simple to you, but I can't grasp the concept. Could you list the steps needed to solve the above problem This question is from textbook prealgebra Answer by stanbon(60778)   (Show Source): You can put this solution on YOUR website!The distance (d) a spring will stretch varies directly as the force (f) applied to the spring. If a force of 12lb is required to stretch a spring 3inchs, what force is required to stretch the spring 5 inches? If d varies directly with f the math way of saying this is d=kf where k is a constant of proportionality. In these problems you are usually given enough information to find k, as follows: 3=k(121) k=3/121 So for your spring the proper equation relating distance and force is d=(3/121)f Now you are asked what force is required to stretch the spring 5 inches. So, 5=(3/121)f Multiply both sides by 121 to get: 605=3f Divide both sides by 3 to get: 201.67= f That is the required force. Cheers, Stan H.