SOLUTION: 8(.09-.7x)+1.259<=.091+18x Solve and put in interval format Please help! I'm missing something! I tried .72-5.6x+1.259<=.091+18x -5.6x+1.979<=.091+18x -5.6x+1.888<=18x 1.888

Question 99757: 8(.09-.7x)+1.259<=.091+18x
Solve and put in interval format
Please help! I'm missing something!
I tried
.72-5.6x+1.259<=.091+18x
-5.6x+1.979<=.091+18x
-5.6x+1.888<=18x
1.888<=23.6x
.08<=x
x>=.08
[.08, inf)

Found 2 solutions by jim_thompson5910, stanbon:
Answer by jim_thompson5910(35256) (Show Source): You can put this solution on YOUR website!
Start with the given inequality

Distribute

Multiply both sides by 1000. This will eliminate all of the decimals

Combine like terms on the left side

Subtract 1979 from both sides

Subtract 18000x from both sides

Combine like terms on the left side

Combine like terms on the right side

Divide both sides by -23600 to isolate x (note: dividing by both sides by a negative number flips the inequality sign)

Divide

So our answer is which is

[)

in interval notation
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
That looks good.
Cheers,
Stan H.
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