SOLUTION: This should be easy, but no combination seems to come out "correct" according to my submission. It's supposed to be solved and put in interval format. 7x+12<=6 So I tried sub

Algebra ->  Algebra  -> Inequalities -> SOLUTION: This should be easy, but no combination seems to come out "correct" according to my submission. It's supposed to be solved and put in interval format. 7x+12<=6 So I tried sub      Log On

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Question 99754: This should be easy, but no combination seems to come out "correct" according to my submission. It's supposed to be solved and put in interval format.
7x+12<=6
So I tried
subtract 12 from bothsides 7x<=-6
then divide by 7 for x<=-6/7
So interval format should be (inf, -6/7]
But I'm wrong. Please help! Thanks!
Found 2 solutions by jim_thompson5910, staciie21:
Answer by jim_thompson5910(21667) About Me  (Show Source):
You can put this solution on YOUR website!
7x%2B12%3C=6 Start with the given inequality


7x%3C=6-12Subtract 12 from both sides


7x%3C=-6 Combine like terms on the right side


x%3C=%28-6%29%2F%287%29 Divide both sides by 7 to isolate x


--------------------------------------------------------------
Answer:
So our answer is x%3C=%28-6%29%2F%287%29


Since x can be any number less than %28-6%29%2F%287%29, this means our left endpoint is negative infinity and our right endpoint is %28-6%29%2F%287%29.


So the answer in interval notation is :


(-, -6%2F7]

Answer by staciie21(2) About Me  (Show Source):
You can put this solution on YOUR website!
its an open sentence cause it has a letter
for example what is x?