No your mistake is on the second line. The -4 should be a +4. You changed the sign of both the expression and the 4. That's wrong. You only change the sign on ONE side, not both. The 3x+2 > 4 is correct, and x > 2/3 is correct. Here is the correction: The problem is |3x+2| > 4. This is what I tried: 3x+2 > 4 or -3x-2>4 3x > 2 or -3x>6 x > 2/3 or x < -2 What's between a pair of absolute value bars can either be what's there or the negative of what's there because |5| and |-5| are the same thing> So the 5 can either have an understood positive sign before it or a written negative sign before it. But the right side (the number) doesn't change signs. To graph that draw a numberline and mark -2 and 2/3 with open circles. 2/3 is located two-thirds of the way between 0 and 1: <==============o----------------o=============> -4 -3 -2 -1 0 1 2 3 The interval notation for that isEdwin