SOLUTION: solve and graph the solution: 57 -4t is greater than or equal to 13

Question 93532: solve and graph the solution:
57 -4t is greater than or equal to 13
Answer by jim_thompson5910(35256) (Show Source): You can put this solution on YOUR website!

Subtract 57 from both sides

Combine like terms on the right side

Divide both sides by -4 to isolate t (note: multiplying/dividing a negative number on both sides flips the sign of the inequality)

Reduce

--------------------------------------------------------------
Answer:
So our answer is

Now let's graph

Set up a number line:
note: just replace the x with the variable you are working with

Now plot the point t=11 on the number line

Now pick any test point you want, I'm going to choose t=0, and test the inequality

Plug in

Since this inequality is true, we simply shade the entire portion in which contains the point t=0 using the point t=11 as the boundary.This means we shade everything to the left of the point t=11 like this:
Graph of with the shaded region in blue
note: at the point t=11, there is an closed circle. This means the point t=11 is included from the solution set.

RELATED QUESTIONS
57-4t is greater or equal to... (answered by mananth)

Solve and graph the solution: x+1 is greater than or equal to 7 and -6x is greater than... (answered by jsmallt9)

Solve the inequality. Then identify the solution of the inequality. 1/4t is less than... (answered by lwsshak3)

Can someone please solve and notate the solution? -8x is greater than or equal to -7.2 (answered by Alan3354)

Solve and Graph The Absolute Value of y-6 is greater than or equal to 5 (answered by Alan3354)

Solve and graph the following inequalities. If there is no solution, write DNE. If all... (answered by CubeyThePenguin)

Solve each inequality. graph the solution set. 4-xIS GREATER THAN OR EQUAL TO... (answered by stanbon)

Solve and graph the solution 8x+5> 7x+8 _ (answered by jim_thompson5910)

Solve and graph the solution set of the following inequality. I need to show my work... (answered by ankor@dixie-net.com)