SOLUTION: solve the system using elimination: 0.2x+0.3y=.08 0.3x+0.4y=1.3

Question 887212: solve the system using elimination:
0.2x+0.3y=.08
0.3x+0.4y=1.3
Answer by grishma.kshatriya(27) (Show Source): You can put this solution on YOUR website!
Solution :
To solve using the elimination method we first eliminate one of the variable with same co-efficient but opposite signs and then find the solution .
0.2x+0.3y=.08.......(1)
0.3x+0.4y=1.3.......(2)
To simplify it we will multiply each term by 10 we get ,
2x + 3y = 0.8......(1)
3x + 4y = 13.......(2)
Multiply (1) by 4 and the (2) by 3 ,
We get ,
8x + 12y = 3.2....(1)
9x + 12y = 39 ....(2)
Subtracting both the equation we get ,
8x + 12y = 3.2
- 9x + 12y = 39
- - -
-------------------
- x + 0 y = - 35.8
So we have x = 35.8
Now plug the x = 35.8 in one of the equation we get ,
3 * (35.8) + 4y = 13
y = - 23.6
So the solution is (35.8 , -23.6)

Thank you .
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