SOLUTION: The length of the rectangle is 3 times its width. The perimeter of the rectangle is 160 ft. Find the length and the width of the rectangle. Solve the problem algebraically.
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Question 87379: The length of the rectangle is 3 times its width. The perimeter of the rectangle is 160 ft. Find the length and the width of the rectangle. Solve the problem algebraically.
Answer by Nate(3500) (Show Source): You can put this solution on YOUR website!
width = w
length = 3w
2*width + 2*length = perimeter
2(w) + 2(3w) = 160
2w + 6w = 160
8w = 160
w = 20
width = 20 feet
length = 60 feet
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