Hi,

scores of 68, 65, 75, and 78 on his algebra tests 0r 286 Pts per date

Let x represent the final exam score

 70 ≤ avg ≤79  represents a C in the class

 Question states***to receive a C

 70 ≤(286 + 2x)/6) ≤ 79 

(420-286)/2 ≤ x ≤ (474 - 286)/2

        67 ≤  x  ≤  94 

Answer by TimothyLamb(4379)   (Show Source): You can put this solution on YOUR website!
 (68 + 65 + 75 + 78 + f)/6 = 70

(286 + f)/6 = 70

286 + f = 70*6

286 + f = 420

f = 134

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(68 + 65 + 75 + 78 + f)/6 = 79

(286 + f)/6 = 79

286 + f = 79*6

286 + f = 474

f = 188

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if the final counts as two tests, I assume that max score on the final is 200 (not 100).

if that's true, then:

---

Answer:

134 <= f <= 188

---

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