SOLUTION: How would you go about solving this inequality?
x^3>1
Algebra.Com
Question 768078: How would you go about solving this inequality?
x^3>1
Answer by tommyt3rd(5050) (Show Source): You can put this solution on YOUR website!
x^3>1
x^3-1>0
(x-1)(x^2+x+1)>0
but this is always true: (x^2+x+1)>0
so we only need look at
x-1>0
and thus x>1
:)
RELATED QUESTIONS
How would you go about solving this equation? |-2x+1| + x =... (answered by Alan3354)
How would I go about solving this? The problem tells me to enter the inequality to the... (answered by Alan3354)
2-log3x = log(x/12)
how would you go about solving this... (answered by stanbon)
How would you go about solving this factor?
Solve: 8x^2 + 2x =... (answered by stanbon)
how would you go about solving {{{log (3,... (answered by josgarithmetic)
(1/32)^2x=64^x+1 How would I go about solving... (answered by jim_thompson5910)
Hello, how would you go about solving 343-7(x+3) if x+3 is raised to the second... (answered by stanbon,pie90010)
How would one go about solving the following inequality in interval notation?... (answered by tommyt3rd)
How would you go about solving this factor?
Factor: 4x^2 –... (answered by mathemanic)