SOLUTION: solve the inequalities: 5x-6+3x<2+9x-5? This is what I did.. 5x+3x=8X-6<-3+9x.......because 2-(-5)=-3 then I cancelled the 6 on one side and -3+6=3 then I 8x<3+9x now what d

Question 726565: solve the inequalities:
5x-6+3x<2+9x-5?
This is what I did..
5x+3x=8X-6<-3+9x.......because 2-(-5)=-3
then I cancelled the 6 on one side and -3+6=3
then I 8x<3+9x now what do I do? Do I divide it by 9it would be x<3 it doesn't make sense.
Answer by checkley79(3341) (Show Source): You can put this solution on YOUR website!
5x-6+3x<2+9x-5
8x-6<-3+9x
8x-9x<-3+6
-x<3 ans.
Proof:
Let x=-2.9
5(-2.9)-6+3(-2.9)<2+9(-2.9)-5
-14.5-6-8.7<2-26.1-5
-29.2<2-31.1
-29.2<-29.1
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