5(x + 12) ≥ 3x + 94      undo parenthesis by distributive property

    5(x)+ 12(5) ≥ 3x + 94

        5x + 60 ≥ 3x + 94       since 5x is greater than 3x we are going to subtract 3x both sides

   5x - 3x + 60 ≥ 3x - 3x + 94

        2x + 60 ≥ 94           then subtract 6 both sides to separate the variable

   2x + 60 - 60 ≥ 94 - 60 

             2x ≥ 34         divide 2 both sides so that x will be left

              x ≥ 17 ------>> answer

         



   

    

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