SOLUTION: Solve the inequality 21/15-3x<0 and express the solution as an interval.

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Question 71926: Solve the inequality 21/15-3x<0 and express the solution as an interval.
Answer by bucky(2097) About Me  (Show Source):
You can put this solution on YOUR website!
21%2F15-3x%3C0
.
Add +3x to both sides and you get:
.
+21%2F15+%3C+3x
.
Notice that 21%2F15 can be factored to %283%2A7%29%2F%283%2A5%29. In this the 3 in the numerator
cancels with the 3 in the denominator. This reduces the 21%2F15 to 7%2F5. The inequality
then becomes:
.
7%2F5+%3C+3x
.
Finally, divide both sides of the inequality by 3 to find:
.
%287%2F5%29%2F3+%3C+x
.
When the division on the left side is done the result is 7%2F%285%2A3%29+=+7%2F15 so the inequality
is then solved as:
.
7%2F15+%3C+x
.
This shows that x is any value that is greater than 7%2F15. In decimal form 7/15 = 0.4666...
so you can mark 0.4666 ... on the number line then show that x lies at anywhere to the right
of that point ... as far as you can go.
.
Hope this helps you to understand how to handle inequalities. For most cases you can
perform math operations just as you would an equation. One exception is that if you multiply
or divide both sides by a negative number, you have to reverse the direction of the inequality
sign. In this problem we did not have to multiply or divide BOTH sides by the same negative
number. Therefore, we didn't have to reverse the inequality direction. But in some
problems you will have to in order to solve for +x.