SOLUTION: 101=13f - 2(4+3f)

Algebra.Com
Question 695222: 101=13f - 2(4+3f)
Answer by edjones(8007)   (Show Source): You can put this solution on YOUR website!
101=13f-2(4+3f)
...=13f-8-6f
...=7f-8
109=7f
f=109/7
.
Ed

RELATED QUESTIONS

-2/3f+3<-9 (answered by jim_thompson5910)
How do I solve: 1) 1/3f = 4 - 2/3f 2) 3q - 5/8 = 0 Thank you... (answered by stanbon)
(6f2 - 13 - 11f) ÷ (3f -... (answered by rfer)
{3f+10} less than... (answered by rfer)
3(3F-4)>4F-8 (answered by JulietG)
3(3f-4)>5f-9 (answered by MathLover1)
2f-f*f+4-10f+3f (answered by tommyt3rd)
8(2f-2)=7(3f+2) (answered by stanbon,MathLover1)
Simplify each expression 1. 3f^3f^4 2. (m^4n) ^5 3. ( 8a^2b^-3)^4(3ab^-2)^-4 4. (8^3) (answered by MathLover1)