SOLUTION: please help me solve 8(y+2)=2(3y+4) i tried 8y+16=6y+8 8y+6y=16+8 14y=24 then what?

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Question 675739: please help me solve
8(y+2)=2(3y+4)
i tried
8y+16=6y+8
8y+6y=16+8
14y=24
then what?
Found 3 solutions by jpvn2015, ewatrrr, ReadingBoosters:
Answer by jpvn2015(54)   (Show Source): You can put this solution on YOUR website!
8(y+2) = 2(3y+4)
Which equals = 8y + 16 = 6y + 8
Then, we subtract 6y from both sides and get: 2y + 16 = 8
Subtract 16 from sides: 2y = -8
Thus, y = -4

Answer by ewatrrr(24785)   (Show Source): You can put this solution on YOUR website!
 

Hi

8(y+2)=2(3y+4)

 8y+16=6y+8   Yes.  Good work

8y + 16 -6y-16  = 6y + 8 - 6y - 16    ||Combining Like Terms(variable on one side,numbers on the other

    2y = -8

     y = -4 

Answer by ReadingBoosters(3246)   (Show Source): You can put this solution on YOUR website!
 Distribute the 8 and the 2

8(y) + 8(2) = 2(3y) + 2(4)

...

8y + 16 = 6y + 8

Isolate y to one side of the equation

Subtract 6y from both sides

Subtract 16 from both sides

8y - 6y = 8 - 16

...

2y = -8

Divide both sides by 2



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