SOLUTION: What is the solution? x(3-x) + 2x(x-1)_<(less than or equal too).. x^2

SOLUTION: What is the solution? x(3-x) + 2x(x-1)_<(less than or equal too).. x^2 - 3x + 12

Question 674291: What is the solution?
x(3-x) + 2x(x-1)_<(less than or equal too).. x^2 - 3x + 12
Answer by jokaehler(26) (Show Source): You can put this solution on YOUR website!
x(3-x) + 2x(x-1)_<(less than or equal too).. x^2 - 3x + 12

First, we need to use the distributive property on the left side of the equation. (x * 3) + (x * -x) + (2x * x) + (2x * -1)
Which turns out to be...

Then, we need to get "x" on one side (I like "x" on the left side). Subtract "" and add "" to both sides.
We end up with...
4x (is less than or equal to) 12
Divide both sides by "4," and we end up with...
x (is less than or equal to) 3
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