SOLUTION: In a bag of marbles, 2/5 are red, 2/7 are green, & the rest are blue. What fraction of the marbles are blue? Thanks! Please work really really really fast! Happy H

Question 64997This question is from textbook Pre-Algebra
: In a bag of marbles, 2/5 are red, 2/7 are green, & the rest are blue. What fraction of the marbles are blue?

Thanks! Please work really really really fast! Happy Holidays! This question is from textbook Pre-Algebra

Found 2 solutions by funmath, ptaylor:
Answer by funmath(2933) (Show Source): You can put this solution on YOUR website!
In a bag of marbles, 2/5 are red, 2/7 are green, & the rest are blue. What fraction of the marbles are blue?
:
The LCD of 5 and 7 is 35, so there are 35 marbles, all of the marbles is 35/35.

are blue.
Happy Calculating!!!!
Answer by ptaylor(2198) (Show Source): You can put this solution on YOUR website!
2/5 are red, 2/7 are green, & the rest are blue
The blue marbles=1-(2/5+2/7)
The lowest common multiple for 7 and 5 is 35 so we multiply everything by 35/35 and we get:

The blue marbles=35/35-(2/5)(35/35)-(2/7)(35/35) simplifying, we have:
The blue marbles=35/35-((2)(7))/35-(2)(5))/35 further simplifyinig:
The blue marbles=35/35-14/35-10/35=
The blue marbles=(35-24)/35=11/35
11/35 is the fraction of the marbles that is blue

CK
35/35=11/35+2/5+2/7
35/35=11/35+14/35+10/35
35/35=35/35 or
1=1

Hope this helps. Happy holidays----ptaylor

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