SOLUTION: 4(4k+2)-8(k-1) ≤ 3(2k+2)-1
Thats a less than or equal to sign incase its hard to see.
Type the solution set in interval notation. Thanks to whoever can help! :)
Algebra.Com
Question 642622: 4(4k+2)-8(k-1) ≤ 3(2k+2)-1
Thats a less than or equal to sign incase its hard to see.
Type the solution set in interval notation. Thanks to whoever can help! :)
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
4(4k+2)-8(k-1) ≤ 3(2k+2)-1
16k + 8 - 8k + 8 <= 6k + 6 -1
--------
8k +16 <= 6k + 5
2k <= -11
k <= -11/2
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Cheers,
Stan H.
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