SOLUTION: solve the equation in the real number system
x^4-x^3+2x^2-4x-8=0
Algebra.Com
Question 628610: solve the equation in the real number system
x^4-x^3+2x^2-4x-8=0
Answer by Alan3354(69443) (Show Source): You can put this solution on YOUR website!
solve the equation in the real number system
x^4-x^3+2x^2-4x-8=0
---------------
4th orders can be tough.
Step 1, check for integer solution.
Those would be the factors of 8.
1 & 2 plus and minus
RELATED QUESTIONS
Solve the equation in the real number system: x^8-4x^7+3x^6+8x^5-15x^4+4x^3+9x^2-8x+2=0
(answered by ikleyn)
Solve the equation in the real number system.
{{{ 2x^3-x^2-6x+3=0 }}}
(answered by MathLover1)
Hello how do I solve
X^4-X^3+2X^2-4x-8=0
Using the real number system?
Please... (answered by Alan3354)
Solve the equation in the real number system. x^4 - 3x^3 + 5x^2 - x - 10 =... (answered by josgarithmetic)
Can you help solve the equation in the real number system... (answered by Alan3354)
Solve the equation in the real number system... (answered by Edwin Parker)
Solve the equation in the real number system.
X^4-3x^3+12x^2-48x-64=0
(answered by lwsshak3)
Hello!
How do I solve the polynomial using the real number system?
X^4-X^3+2X^2-4x-8
(answered by Alan3354)
Solve equation in real number system. List real solution(s) x=. must show all work.... (answered by Fombitz)