SOLUTION: COULD SOMEONE HELP ME WITH THIS PROBLEM: A university bookstore recently sold a wirebound graph-paper notebook for $3.36, and a college-ruled notebook for $4.57. At the start o

Question 614855: COULD SOMEONE HELP ME WITH THIS PROBLEM:
A university bookstore recently sold a wirebound graph-paper notebook for $3.36, and a college-ruled notebook for $4.57. At the start of spring semester, a combination of 50 of these notebooks were sold for a total of $205.51. How many of each type were sold?

Answer by Theo(13342) (Show Source): You can put this solution on YOUR website!
x = number of wire bound notebooks
y = number of college ruled notebooks
x + y = 50
3.36 * x + 4.57 * y = 205.51
solve these 2 equations simultaneously to get your answer.
from the first equation, solve for y to get:
y = 50 - x
substitute this value of y in the second equation to get:
3.36 * x + 4.57 * (50-x) = 205.51
simplify to get:
3.36 * x + 4.57 * 50 - 4.57 * x = 205.51
combine like terms to get:
-1.21 * x + 228.5 = 205.51
subtract 228.5 from both sides of the equation to get:
-1.21 * x = -22.9
divide both sides of this equation by -1.21 to get:
x = -22.9 / -1.21 = 19
since x + y = 50, this means that y = 31
3.36 * 19 + 4.57 * 31 = 205.51
numbers check out.
answer is:
number of wire bound notebooks is 19 and number of college ruled notebooks is 31.

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