SOLUTION: I need your help solving this,$9500 is invested, part at 11% and the other is at 6%. for a certain year the total was $65.00

Question 590905: I need your help solving this,$9500 is invested, part at 11% and the other is at 6%. for a certain year the total was $65.00
Answer by josmiceli(19441) (Show Source): You can put this solution on YOUR website!
Let = amount invest @ 11%
Let = amount invested @ 6%
given:
(1)
(2)
-------------------
(2)
Multiply both sides of (1) by and
subtract (2) from (1)
(1)
(2)

The minus sign means it is not possible
Suppose all the money was invested at 6%

That's more than $65
I bet the $65 should be $650
Check it
RELATED QUESTIONS
$9500 is invested, part of it at 10% and part of it at 6%. for a certain year, the total... (answered by jorel1380)

$9500 is invested, part of it is 11% and part of it is 6%. For a certain year, the total... (answered by rwm)

$9500 is invested, part of it at 11% and part of it at 7%. For a certain year, the total... (answered by ewatrrr)

$9500 is invested,part of it at 11% and part of it at 9%. For a certain year, the total... (answered by Boreal)

$9500 is invested, part of it at 10% and part of it at 6%. For a certain year, the total... (answered by richwmiller)

If an investment is $9500, part of it at 11% and part of it at 8%. For a certain year (answered by checkley79)

$5400 is invested, part of it at 11% and part at 6% for a certain year the total yield is (answered by richwmiller)

Happy Holidays Tutors, HELP HELP I need help understanding how to work algebra word... (answered by josgarithmetic)

$9500 is invested, part of it at 10% and part of it at 8%. For a certain year, the total... (answered by robertb)