SOLUTION: the sum of three consecutive odd integers is less than 100. What are the greatest possible values of these integers?
x= 1st odd integer
x+2= 2nd odd integer
x+4= 3rd odd integer
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Question 57475This question is from textbook
: the sum of three consecutive odd integers is less than 100. What are the greatest possible values of these integers?
x= 1st odd integer
x+2= 2nd odd integer
x+4= 3rd odd integer
x+x+2+x+4<100
3x+6<100
-6 -6
3x<94
dived by 3 both sides
equals
x<31 and one third
This question is from textbook
Answer by funmath(2933) (Show Source): You can put this solution on YOUR website!
the sum of three consecutive odd integers is less than 100. What are the greatest possible values of these integers?
x= 1st odd integer
x+2= 2nd odd integer
x+4= 3rd odd integer
x+x+2+x+4<100
3x+6<100
-6 -6
3x<94
dived by 3 both sides
equals
x<31 and one third
~~~~~~~~~~~~~~~~~~
You've done everything right so far. You just need to finalize your thoughts and calculations.
Because you need them to be integers:
x<31 (without the one third)
The first odd integer: X=31
The second odd integer: x+2=33
The third odd integer: x+4=35
:
Check:
31+33+35=99
If you went with 33+35+37=105 So you're right:-)
Happy Calculating!!!
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