SOLUTION: THE LENGTH OF A RECTANGLE IS 3IN MORE THAT TWICE IT'S WIDTH. iF THE PEREMETER OF THE RECATNGLE IS 36 INC FIND THE WIDTH OF THE RECTANGLE. tHANK YOU SOOOO MUCH. yOU ALL HAVE HELP

Question 56004: THE LENGTH OF A RECTANGLE IS 3IN MORE THAT TWICE IT'S WIDTH. iF THE PEREMETER OF THE RECATNGLE IS 36 INC FIND THE WIDTH OF THE RECTANGLE.
tHANK YOU SOOOO MUCH. yOU ALL HAVE HELPED ME SO MUCH
Answer by Lacey020991(49) (Show Source): You can put this solution on YOUR website!
The length of the rectangle (l) = 2w+3 (twice the width plus 3 in)
The width of the rectangle (w) = w
l = 2w+3
w = w
P = 2l + 2w
36 = 2(2w+3) + 2w ++++++ distribute the 2
36 = 4w + 6 + 2w +++++++ combine like terms
36 = 6w + 6 ++++++++++++ subtract 6 from each side
30 = 6w ++++++++++++++++ divide each side by 6
5 = w
The width of the rectangle would be 5
The length would be 13
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