SOLUTION: If 49-5x<=27-x,find: (a)the smallest value of x,when x is a real number. (b)the smallest value of x,when x is an integer.

Algebra.Com
Question 551369: If 49-5x<=27-x,find:
(a)the smallest value of x,when x is a real number.
(b)the smallest value of x,when x is an integer.

Answer by fcabanski(1391)   (Show Source): You can put this solution on YOUR website!
First solve it. It's just like solving an equation, but if when dividing by a negative number flip the inequality.


49-5x <= 27-x || Add x to both sides and subtract 49 from both sides
-4x <= -22 || Divide both sides by -4, flip the inequality.
x >= 5.5


A) When x is a real number the smallest value is 5.5.
B) When x is an integer the smallest value is 6. When the digit to be rounded is 5 or more round up. 5.5 rounded to the nearest integer is 6.

If you need help understanding math so you can solve these problems yourself, then one on one online tutoring is the answer ($30/hr). If you need faster solutions with guaranteed detailed answers, then go with personal problem solving ($3.50-$5.50 per problem). Contact me at fcabanski@hotmail.com


RELATED QUESTIONS

Given that 4x/5 – 1/10 ≤ x –2/5, state the smallest value of x when: i) x is an... (answered by RAY100)
find the smallest value of 4x^2+4x , if x is real... (answered by Alan3354)
Y=sqrt10+x What is the smallest positive value of x that makes y an... (answered by ikleyn)
Find the smallest value of a positive integer x such that x^2 + 4 is divisible by 25.... (answered by Sphinx pinastri)
If 6x-4<8x+12, what is the smallest possible integer value of... (answered by oscargut)
When 1000 is divided by some positive integer x, the remainder is 45. What is the sum of... (answered by ikleyn)
The smallest integer in a set of three consecutive integers is x, and the largest... (answered by mananth)
If a and b are positive real numbers and each of the equations {{{ x^2+ax+2b=0}}} and... (answered by swincher4391)
The product of 504 and a anumber X is a square number. What is the smallest possible... (answered by jsmallt9)