SOLUTION: tickets for a train $120 for sleeping room $80 for berth and $50 for coach the total sales were $8600 If there were 20 more berth than sleeping and 3 time as many coach as sleeping

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Question 53951: tickets for a train $120 for sleeping room $80 for berth and $50 for coach the total sales were $8600 If there were 20 more berth than sleeping and 3 time as many coach as sleeping how many of each type were sold. I am just having problem with the formula after i get that i can keep going i cant get if its x+2(c)=8600 Or c(x+2)=8600 even then i can figure it out after that there must be something with the amounts or its a two part problem just get me the 1st step Thanks
Answer by ankor@dixie-net.com(22740) About Me  (Show Source):
You can put this solution on YOUR website!
tickets for a train $120 for sleeping room $80 for berth and $50 for coach
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the total sales were $8600
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Let s = no. of sleeping rms; Let b = no. of berths; Let c = no. of coaches
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If there were 20 more berth than sleeping
b = s + 20
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and 3 time as many coach as sleeping
c = 3s
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how many of each type were sold.
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120s + 80b + 50c = 8600
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Substitute (s+20) for b; and 3s for c; in above eq, and solve for s
:
This should help you.