# SOLUTION: Angela needs 20 quarts of 50% antifreeze solution in her radiator. She plans to obtain this by mixing some pure antifreeze with an appropriate amount of a 40% antifreeze solution.

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 Question 52659: Angela needs 20 quarts of 50% antifreeze solution in her radiator. She plans to obtain this by mixing some pure antifreeze with an appropriate amount of a 40% antifreeze solution. How many quarts of each solution should she use? 100% antifreeze? qts + 40% solution ? qts = 50% solution qts Answer by stanbon(57282)   (Show Source): You can put this solution on YOUR website!Angela needs 20 quarts of 50% antifreeze solution in her radiator. She plans to obtain this by mixing some pure antifreeze with an appropriate amount of a 40% antifreeze solution. How many quarts of each solution should she use? 100% antifreeze? qts + 40% solution ? qts = 50% solution qts ----------------------- Let amount of 40% solution be "x"; active ingrediant is 0.40x qts. Amount of 100% solution is "20-x" qts; active ingrediant is (20-x) qts Amount of mixed solution is 20 qts ; active ingrediant 0.50*20=10 qts. EQUATION: active + active = active 0.4x + 20-x = 10 -0.6x=-10 x= 16 2/3 qts. She should use 16 2/3 qts. of 40% solution. Cheers, Stan H.