SOLUTION: 0.6(x-50)=18-0.3(40-10x)

Algebra.Com
Question 52590: 0.6(x-50)=18-0.3(40-10x)
Answer by terbear1963(43)   (Show Source): You can put this solution on YOUR website!
0.6(x-50)=18-0.3(40-10x) ---> 10(0.6x-30)=(18-12+3x)10 ---> 6x-300=180-120+30x ---> 6x-300=60+30x ---> -360=24x ---> x=-15 I hope this helps you out!? Your math friend, Terry cats7051@yahoo.com
RELATED QUESTIONS

0.6(x-50)=18-0.3(40-10x) (answered by funmath)
x^2 -10x... (answered by tommyt3rd)
10x^2+x-3=0. (answered by jim_thompson5910)
10x^2-X-3=0 (answered by Fombitz)
x^6-3x^3-18=0 (answered by stanbon)
x^6-3x^3-18=0 (answered by Fombitz)
1. x^2+6x-5=0 2. 4x^2 + 20x = 0 3. 3x^2 + 10x + 8 = -17x - 2 4. x^2 + 3x - 40 =... (answered by jim_thompson5910)
sin(x+40)+sin(x+50)=0 (answered by MathLover1)
2x squared + 10x = -3 and x squared + 10x - 7 =... (answered by stanbon)