SOLUTION: In a chemistry class, 12L of a 12% alcohol solution must be mixed with a 20% solution to get a 14% solution. How many liters of the 20% solution are needed? Thank you very mu

Question 52509This question is from textbook Intermediate Algebra
: In a chemistry class, 12L of a 12% alcohol solution must be mixed with a 20% solution to get a 14% solution. How many liters of the 20% solution are needed?
Thank you very much! This question is from textbook Intermediate Algebra

Found 2 solutions by stanbon, Nate:
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
In a chemistry class, 12L of a 12% alcohol solution must be mixed with a 20% solution to get a 14% solution. How many liters of the 20% solution are needed?
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12% fluid DATA:
amount = 12 liters ; active ingredient = 0.12(12) = 1.44 liters
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20% fluid DATA:
amount = x liters ; active ingredient = 0.20x liters
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14% fluid DATA:
amount = 12+x liters ; active ingredient = 0.14(12+x)= 1.68+0.14x liters
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EQUATION:
active + active = active
1.44 + 0.20x = 1.68+0.14x
0.06x=0.24
x=4 liters (amount of 20% fluid to be added)
Cheers,
Stan H.
Answer by Nate(3500) (Show Source): You can put this solution on YOUR website!

I hope that is right; my calculator is upstairs, and I am too lazy to go fetch it, so I did it in my head instead. I have full confidence in you checking it.
Good Luck,
N2^3
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