SOLUTION: Sometimes one is only given the slope and a point not on the y-axis and asked to find the equation of the line going through those two points. One of two very nice methods for doin

Question 508416: Sometimes one is only given the slope and a point not on the y-axis and asked to find the equation of the line going through those two points. One of two very nice methods for doing this is to use the Point-Slope Formula (given below). Given the slope of 3 and the point (1, 5), use the point slope formula, to write the equation for this line.
y-y1(1 should be lower)= m(x-x1(1 should be lower...
m is the slope and (x1(1 should be lower),y1(1 should be lower) is the point)
(when i say the 1 should be lower it should be like like y^1 but its on the bottom rightnot top)
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
Given the slope of 3 and the point (1, 5), use the point slope formula, to write the equation for this line.
y-y1 = m(x-x1)
---
y-5 = 3(x-1)
---
y -5 = 3x-3
y = 3x-3+5
---
y = 3x+2
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Cheers,
Stan H.
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