SOLUTION: 2(y)^1/9 - 3 (y)^1/18 + 1 = 0 I've got it broken down to (2y^1/18 -1)(y^1/18 - 1) = 0 I'm confused as to what the next step is and how to get there! Thanks so much, Trac

Question 501818: 2(y)^1/9 - 3 (y)^1/18 + 1 = 0
I've got it broken down to
(2y^1/18 -1)(y^1/18 - 1) = 0
I'm confused as to what the next step is and how to get there!
Thanks so much,
Tracy
Answer by htmentor(1343) (Show Source): You can put this solution on YOUR website!
2(y)^1/9 - 3 (y)^1/18 + 1 = 0
I've got it broken down to
(2y^1/18 -1)(y^1/18 - 1) = 0
========================================
To avoid working with fractional exponents, let x = y^(1/18)
Then we can rewrite the equation as:

This can be factored as:
(2x-1)(x-1) = 0
The solutions are x = 1/2, x = 1
Therefore 1 = y^(1/18) -> y = 1
For the other root, 1/2 = y^(1/18)
To solve for y raise both sides to the 18th power:
(1/2)^18 = y
So the two roots are 1 and (1/2)^18

RELATED QUESTIONS
y(y-7)=18 y^2-7y+18=0 from here I couldn't get the middle term I tried(y-9)(y-2) which (answered by stanbon)

2y^2-x^2=18. Solve to find asymptopes for a hyperbola. I know that the form for the... (answered by venugopalramana)

1. 3x -2y =0 x^2+(y-1)^2=11 2. 6x +12y^2-18=0 y+3x-9=0 3.12x^2-y^2-12=0... (answered by Alan3354)

complete the ordered pairs,(1,_) and (_,9) so they satisfy the equation y=-9x +18. this... (answered by Alan3354)

1/2y-... (answered by Fombitz)

I think I solved this correctly, but just wanted to check: 9y+3x=18; -3y-x=-6... (answered by Alan3354,rothauserc)

Minimize z=4x+7y subject to... (answered by ikleyn)

Please help me solve this equation: 1/6(3y-2)=1 -1/3(y-1) This is what I have come up (answered by jim_thompson5910,stanbon)

The problem asks to find the vertex and graph the following quadratic function. y=-x+6x (answered by scott8148,solver91311)