SOLUTION: here are my quaestions for two seperate equations first what is
x+4<2
and then what is
3x+3<6?
Algebra.Com
Question 490636: here are my quaestions for two seperate equations first what is
x+4<2
and then what is
3x+3<6?
Answer by richard1234(7193) (Show Source): You can put this solution on YOUR website!
Those are inequalities, not equations. Equations have = signs.
For the first one, x+4 < 2, subtract 4 from both sides, x < -2.
For the second one, subtract 3 from both sides to obtain 3x < 3, then divide both sides by 3 to get x < 1 as your solution set.
RELATED QUESTIONS
To whomever gets this problem. I know that this is probably in the wrong catagory but I... (answered by longjonsilver)
Okay this is a really long problem that my math teacher gave me :-( and i'm stuck.... (answered by venugopalramana)
Two planes start from the same airport and fly in opposite directions. The second plane... (answered by Edwin McCravy)
My question is in reference to one involving "Solving systems of linear equations by the... (answered by Earlsdon)
Would greatly appreciate help! I need to graph the following system of linear equations:
(answered by jim_thompson5910)
Here is my problem: There are two geometric sequences with 3rd term 5 and 5th term 80.... (answered by jim_thompson5910)
Expectations
As this is a fundamental "hands on" course, it is expected that you master... (answered by ewatrrr)
"I'm thinking of creating three layers: two that have the same general shape and are... (answered by ikleyn)
The perimeter of a rectangular concrete slab is 82 feet and its area is 418 square feet.... (answered by rapaljer)