SOLUTION: Problem: The cost for a long distance telephone call is 0.36 cents for the first minute and 0.21 cents for each additional minute or portion thereafer. Write an inequality repr

Question 47680This question is from textbook Beginning Algebra
: Problem:
The cost for a long distance telephone call is 0.36 cents for the first minute and 0.21 cents for each additional minute or portion thereafer. Write an inequality representing the number of minutes a person could talk without exceeding $3.00
This is what I have so far and I am stuck.
A _<_ 300 cents($3)
This is for the first minute 0.036+B<300
LET x be the number of minutes , each minute will cost 0.21 cents
so the B is 0.21X
0.036 + 0.21X<300.......1
But x I know cannot be a negative so I do not know what to do.
Please advise.
I hope what I wrote makes sense I could not get my equation editor to paste thesign with a line on it.This question is from textbook Beginning Algebra

Answer by stanbon(48545) (Show Source):
You can put this solution on YOUR website!
The cost for a long distance telephone call is 0.36 cents for the first minute and 0.21 cents for each additional minute or portion thereafer. Write an inequality representing the number of minutes a person could talk without exceeding $3.00
Let "x" be the number of minutes a person talks.
Cost= 0.36 + (x-1)0.21
If you want the cost to be <=$3.00 you have the following:
0.36 +(x-1)0.21<=3
Multiply thru by 100 to get rid of the decimals, as follows:
36 + (x-1)(21)<=300
(x-1)<=12.57
x<=13.57 minutes
Cheers,
Stan H.