SOLUTION: i need your help... can you graph this equation? y=-(x-4)^2+3
*state weather the graph opens upward or downwards?
*is the vertex of the graph a maximum or minimum point?
*find t
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Question 447948: i need your help... can you graph this equation? y=-(x-4)^2+3
*state weather the graph opens upward or downwards?
*is the vertex of the graph a maximum or minimum point?
*find the vertex of the graph of the functon?
*what is the axis of symmetry?
*identify the transformation of the graph (how did you mave the parabola)?
Found 2 solutions by stanbon, Gogonati:
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
i need your help... can you graph this equation? y=-(x-4)^2+3
*state weather the graph opens upward or downwards?
down because of the negative on the (x-4)^2
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*is the vertex of the graph a maximum or minimum point?
max because the graph goes down from the vertex.
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*find the vertex of the graph of the function?
Vertex: (4,3)
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*what is the axis of symmetry?
x = 4
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*identify the transformation of the graph (how did you move the parabola)?
x-4 moves the parabola to the 4 to the right.
3 moves the graph up 3 units.
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Cheers,
Stan H.
Answer by Gogonati(855) (Show Source): You can put this solution on YOUR website!
The graph is a downward parabola, its vertex is the point (4, 3) and the axis of symmetry is the line x=4.
To construct the graph we start from :1) reflect to the x-axis
,
2)shift 4 units to the right shift 3 units up
. See the graph below:
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