SOLUTION: Identify the vertex , axis of symmetry, and direction of opening for
y=2(x+3)^2-5.
Thanks
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Question 43486: Identify the vertex , axis of symmetry, and direction of opening for
y=2(x+3)^2-5.
Thanks
Found 2 solutions by Nate, venugopalramana:
Answer by Nate(3500) (Show Source): You can put this solution on YOUR website!
This is a vertical parabola. Since the value is positive, the parabola opens upward.
Vertex: (h,k) for form:
Vertex: (-3,-5)
For the axis of symmetry, look at the x-value in the vertex.
Axis of Symmetry:
Answer by venugopalramana(3286) (Show Source): You can put this solution on YOUR website!
Identify the vertex , axis of symmetry, and direction of opening for
y=2(x+3)^2-5.
axis of symmetry is x+3=0...or....x=-3...then y=-5 .hence vertex is (-3,-5)
y =-5 for x=-3 is the minimum value .hence direction of opening is upwards for the curve.
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