SOLUTION: Prove the following inequality. Then state for which values the LHS equals the RHS. Please show and explain (in simple terms) every step in the solution. a^2 + b^2 >= 2 (a-b-

Question 433306: Prove the following inequality. Then state for which values the LHS equals the RHS.
Please show and explain (in simple terms) every step in the solution.
a^2 + b^2 >= 2 (a-b-1)
Thank you.
Answer by robertb(5830) (Show Source): You can put this solution on YOUR website!
I begin with a generally true statement, which is

<==>
<==>
<==> .
Equality holds only if a = 1 and b = -1. (This is obvious if you look at the first inequality in this proof.)
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