SOLUTION: 17-(4k-2) >= 2(k+3) -68k-34 >= 2k+3 -68k-2k >= 37 -70k >= 37 k >= 37/70 ??????

Question 359795: 17-(4k-2) >= 2(k+3)
-68k-34 >= 2k+3
-68k-2k >= 37
-70k >= 37
k >= 37/70
??????
Answer by Jk22(389) (Show Source): You can put this solution on YOUR website!
17-(4k-2) >= 2(k+3) | distributivity : a*(b+c)=a*b + a*c

17 - 4k + 2 >= 2k + 6

19 - 4k >= 2k + 6

19 - 6 >= 2k + 4k

13 >= 6k

k <= 13/6
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