SOLUTION: I am trying to solve the below problem but I have question. -7(5y – 2) > 6(6y-1) I first multiplied -35y- -14> 36y-6 Then added 6 to both sides -35y- -14+6>36y -6+6

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Question 349087: I am trying to solve the below problem but I have question.
-7(5y – 2) > 6(6y-1)
I first multiplied
-35y- -14> 36y-6
Then added 6 to both sides
-35y- -14+6>36y -6+6
-35y- -8>36y
I am confused, I am not sure if the next step is correct.

Found 2 solutions by ankor@dixie-net.com, Theo:
Answer by ankor@dixie-net.com(22740)   (Show Source): You can put this solution on YOUR website!
I am trying to solve the below problem but I have question.
-7(5y – 2) > 6(6y-1)
I first multiplied
-35y- -14> 36y-6
Now this should be
-35y + 14 > 36y - 6
Then added 6 to both sides
-35y + 14 + 6 > 36y
-35y + 20 > 36y
Subtract 20 from both sides
-35y - 36y > -20
-71y > -20
y has to be positive, multiply both sides by -1, this reverses the inequality sign
71y < 20
y = <

Answer by Theo(13342)   (Show Source): You can put this solution on YOUR website!
I will solve it for you and then you can see where you went wrong.

problem is:

-7(5y – 2) > 6(6y-1) which can also be written as:

-7*(5*y – 2) > 6*(6*y-1).

The * indicates multiplication and can make things clearer if there is any ambiguity in how the formula is shown.

remove parentheses to get:

-35*y + 14 > 36*y - 6

add 6 to both sides of the equation to get:

-35*y + 20 > 36*y

add 35*y to both sides of the equation to get:

20 > 36*h + 35*y

combine like terms to get:

20 > 71*y

divide both sides of the equation by 71 to get:

20/71 > y

if 20/71 > y, then:

y < 20/71

that should be your answer.

you confirm by substituting in the original equation to see if the equation is true.

take 3 values for y.

pick values that are easy to calculate wherever possible.

take y = 0 which is smaller than 20/71

take y = 20/71 which is equal to 20/71

take y = 1 which is greater than 20/71

if y is smaller than 20/71, the original equation should be true.

if y is greater than or equal to 20/71, the original equation should be false.

the original equation is:

-7(5y – 2) > 6(6y-1)

substitute 0 for y to get:

14 > -6 which is true.

substitute 1 for y to get:

-21 > 30 which is false.

substitute 20/71 for y to get:

4.14084507 > 4.14084507 which is false.

confirmation of y < 20/71 is good since:

when y < 20/71, the original equation is true.

when y >= 20/71, the original equation is false.





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