SOLUTION: Good evening. I am taking a college level business calculus class. We are currently reviewing algebra. I am stuck on one problem. It is: A-5 ---- < -1 A+2 I know t

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Question 341756: Good evening. I am taking a college level business calculus class. We are currently reviewing algebra. I am stuck on one problem. It is:
A-5
---- < -1
A+2

I know to take the -1 times A + 2 to get A - 5 < A + 2 and I know to take the +2 and subtract it from A - 5 to get A - 5 - 2, but what happens to the A on the right side. Is it not supposed to be a 0? I am really confused and lost and, therefore, unable to continue because the rest of this section contains similar problems. Please help me figure this problem out.

Found 2 solutions by stanbon, Edwin McCravy:
Answer by stanbon(75887)   (Show Source): You can put this solution on YOUR website!
A-5
---- < -1
A+2
---------------------
The boundary of the inequality is (A-5)/(A+2) = -1
-------------------
Since the denominator cannot be zero, A cannot be -2.
---
The numerator cannot be zero so A cannot be 5
-------------------------------
To solve the inequality:
1: Draw a number line
2: Plot the values A = -2 and A = 5
3: Check a test value from each of the resulting 3 intervals
to see where the solutions are for the inequality.
----
A-5
---- < -1
A+2
Check A = -10; (-10-5)/(-10+2) < -1, false so no solutions in (-inf,-2)
Check A = 0; (0-5)/(0+2)< -1, true so solutions in (-2,5)
Check A = 10; (10-5)/(10+2) < -1, false so no solutions in (5,+inf)
====
Final solution: -2< A < 5
============
Graph:

============
Cheers,
Stan H.

Answer by Edwin McCravy(20054)   (Show Source): You can put this solution on YOUR website!

The other tutor's solution is incorrect. It should be



Good evening. I am taking a college level business calculus class. We are currently reviewing algebra. I am stuck on one problem. It is:
A-5
---- < -1
A+2

I know to take the -1 times A + 2 to get A - 5 < A + 2

There's one of your errors! -1 times A + 2 is -1(A + 2) and then you
use the distributive principle to remove the parentheses, and
you end up with -A - 2, (not A + 2).

But also when you multiply through by a variable quantity, A + 2, if that
quantity happens to be negative you would have to change the direction
of the inequality.  So 



would only become

 if  which is the same as 

But it would become

 if  which is the same as 

So two cases must be considered to which if either is valid of
if they both are:

Solving the first case

Case 1:

 if  or 

Add A to both sides:

 if 

 if 

Add 5 to both sides

 if 

 if  

Divide both side by 2

 if 

That gives us the solution set:



--------------------

Solving Case 2:

 if  or 

Add A to both sides:

 if 

 if 

Add 5 to both sides

 if 

 if  

Divide both side by 2

 if 

This is a contradiction, since A cannot be greater than 
and at the same time be less than or equal to -2, so the only solution
is given by case 1.



Edwin

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