SOLUTION: x^2+8x+7>0 X^3-x^2-6X>0

Question 338692: x^2+8x+7>0
X^3-x^2-6X>0
Answer by Fombitz(32388) (Show Source): You can put this solution on YOUR website!

Break up the number line into 3 regions.
Region 1: (,)
Region 2: (,)
Region 3: (,)
Choose a point in each region (not an endpoint).
Test the inequality.
If the inequality is satisfied, the region is part of the solution region.
.
.
.
Region 1:

True, this region is part of the solution.
.
.
.
Region 2:

False, this region is not part of the solution.
.
.
.
Region 3:

True, this region is part of the solution.
.
.
.
Solution: (,) U (,)
.
.
----------------------------------------
.
.

Break up the number line into 4 regions.
Region 1: (,)
Region 2: (,)
Region 3: (,)
Region 4: (,)
.
.
.
Follow the same procedure as outlined above to find the solution region.
RELATED QUESTIONS
x^2 + 8x - 7 <... (answered by josgarithmetic)

1. x^2+8x-6=0 2. x^2-7x-8=0 3.... (answered by josgarithmetic)

x^2-8x>0 (answered by stanbon)

x^2-6x-7>0 (answered by xcentaur,khwang)

x^2-6x-3=0 (answered by checkley71)

x^2-6x+3=0 (answered by Boreal,josgarithmetic)

solve... (answered by venugopalramana)

Solve for X: 6x-7(x^1/2)-... (answered by stanbon)

0.8(x-2)+0.7(x+5)-0.6x (answered by CubeyThePenguin)