SOLUTION: x2 - 8x + 16 >= 0 I got x=4 as the answer but I keep getting told it wrong. I could use help trying to figure out the right answer. A for no x B x <= 4 C -4 <= x <= 4 D

Question 330857: x2 - 8x + 16 >= 0
I got x=4 as the answer but I keep getting told it wrong. I could use help trying to figure out the right answer.

A for no x
B x <= 4
C -4 <= x <= 4
D x = 4
E 2 <= x <= 8
F for all x

Found 2 solutions by Fombitz, Alan3354:
Answer by Fombitz(32388) (Show Source): You can put this solution on YOUR website!
You only have 1/2 of the answer.

When you take the square root of both sides you get,
and
and
and
which together makes up (, ).
.
.
.
The function is always greater than or equal to zero as shown in the graph.
.
.
.

Answer by Alan3354(69443) (Show Source): You can put this solution on YOUR website!
Solve
f(x) = x^2 - 8x + 16 = 0

(x-4) = 0
x = 4
-----------
x=4 is the minimum value of the function, f(x) = 0
For all other values, f(x) > 0
--> For all x, f(x) >= 0
--> All x

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