SOLUTION: If 4 apples and 2 oranges equals $1 and 2 apples and 3 oranges equals $0.70, how much does each apple cost? The previous answer confused me.

Algebra ->  Inequalities -> SOLUTION: If 4 apples and 2 oranges equals $1 and 2 apples and 3 oranges equals $0.70, how much does each apple cost? The previous answer confused me.      Log On


   

Question 318828: If 4 apples and 2 oranges equals $1 and 2 apples and 3 oranges equals $0.70, how much does each apple cost?
The previous answer confused me.
Answer by Fombitz(32388) About Me  (Show Source):
You can put this solution on YOUR website!
Let A be the cost of an apple, R the cost of an orange.
"4 apples and 2 oranges equals $1 (100 cents)"
1.4A%2B2R=100
"2 apples and 3 oranges equals $0.70 (70 cents)"
2.2A%2B3R=70
Multiply eq.2 by (-2) and add to eq. 1 to eliminate A,
-4A-6R%2B4A%2B2R=-140%2B100
-4R=-40
R=10
Then use either equation to solve for A.
4A%2B2R=100
4A%2B2%2810%29=100
4A%2B20=100
4A=80
A=20
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Apples cost 20 cents ($0.20) and oranges cost 10 cents ($0.10).