SOLUTION: problem:-2/3z+9 > and = 2/3z+1 I subtracted 2/3z from right side ande added it to the left side. I subtracted 9 from left and added to right. I ended up with -4/3z >and = -8.

Algebra ->  Inequalities -> SOLUTION: problem:-2/3z+9 > and = 2/3z+1 I subtracted 2/3z from right side ande added it to the left side. I subtracted 9 from left and added to right. I ended up with -4/3z >and = -8.       Log On


   

Question 317771: problem:-2/3z+9 > and = 2/3z+1
I subtracted 2/3z from right side ande added it to the left side.
I subtracted 9 from left and added to right.
I ended up with -4/3z >and = -8.
I dont think that is right.

Answer by jim_thompson5910(35256) About Me  (Show Source):
You can put this solution on YOUR website!
-%282%2F3%29z%2B9%3E=%282%2F3%29z%2B1 Start with the given inequality.


3%28-%282%2Fcross%283%29%29z%2B9%29%3E=3%28%282%2Fcross%283%29%29z%2B1%29 Multiply both sides by the LCD 3 to clear any fractions.


-2z%2B27%3E=2z%2B3 Distribute and multiply.


-2z%3E=2z%2B3-27 Subtract 27 from both sides.


-2z-2z%3E=3-27 Subtract 2z from both sides.


-4z%3E=3-27 Combine like terms on the left side.


-4z%3E=-24 Combine like terms on the right side.


z%3C=%28-24%29%2F%28-4%29 Divide both sides by -4 to isolate z. note: Remember, the inequality sign flips when we divide both sides by a negative number.


z%3C=6 Reduce.


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Answer:

So the solution is z%3C=6