SOLUTION: Which of these equations are equivalent to 16? 3[7x-4(x-3)]+1=16 A:9x-2=16 B:9x+37=16 C:17x-2=16 D:17x+13=16 I already know the answer, but how do I find out which one it i

Algebra ->  Algebra  -> Inequalities -> SOLUTION: Which of these equations are equivalent to 16? 3[7x-4(x-3)]+1=16 A:9x-2=16 B:9x+37=16 C:17x-2=16 D:17x+13=16 I already know the answer, but how do I find out which one it i      Log On

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 Click here to see ALL problems on Inequalities Question 288885: Which of these equations are equivalent to 16? 3[7x-4(x-3)]+1=16 A:9x-2=16 B:9x+37=16 C:17x-2=16 D:17x+13=16 I already know the answer, but how do I find out which one it is? Can you show me please? The correct answer is B, Here is what I got so far. 3[7x-4(x-3)]+1 Rewrite problem. 3[7x-4x+12]+1 Distribute the -4 3[3x+12]+1 Combine like terms. That's as far as I got, I do not know where to come from here. Thank you for your time to help me.Answer by richwmiller(9135)   (Show Source): You can put this solution on YOUR website!None of them has x=16 I really don't know what you want. I certainly have no clue what you are doing here 3[7x-4(x-3)]+1=16 nor where you got it. But it looks like you may have combined a couple equations.