SOLUTION: square root(7)< x < square root(37)and x is an integer, then x can have how many different values?
a 3 b 4 c 5 d 8
Algebra.Com
Question 277716: square root(7)< x < square root(37)and x is an integer, then x can have how many different values?
a 3 b 4 c 5 d 8
Answer by edjones(8007) (Show Source): You can put this solution on YOUR website!
sqrt(7)>sqrt(4)=2
sqrt(37)>sqrt(36)=6
x could be 3,4,5,6
.
Ed
RELATED QUESTIONS
square root(7)< x < square root(37)and x is an integer, then x can have how many... (answered by JBarnum,Alan3354)
square root(x (square root x (square root x))) = ?
a) x^7/8 b) x^7/4 c) x^15/16 d) (answered by stanbon)
this one is a pain and I need help!
x^2+8=57
its one of these
a +-square root... (answered by edjones)
this multiple choice is hard someone please help
x^2+8=57
a. +-quare root 65
b.... (answered by TP)
If x is 1, 2, or 3 and y is either 2 or 4, then the product xy can have how many... (answered by checkley77)
For f(x)=15/x^2-1 and g(x) = SQUARE ROOT x+4, find (g degree sign f)(2)
A. square root (answered by jsmallt9)
What are the possible values of x if the distance between the points (x, 3) and (–7, –1)... (answered by richwmiller)
simplify:
3 square root b^2 divided by 4 square root b^3
a. 1 over 12 square... (answered by checkley77)
If h is the function given by h(x)= f(g(x)) where f(x)= 3x^2 -1 and g(x)= the absolute... (answered by stanbon)