SOLUTION: square root(7)< x < square root(37)and x is an integer, then x can have how many different values?
a 3 b 4 c 5 d 8
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Question 277459: square root(7)< x < square root(37)and x is an integer, then x can have how many different values?
a 3 b 4 c 5 d 8
Found 2 solutions by JBarnum, Alan3354:
Answer by JBarnum(2146) (Show Source): You can put this solution on YOUR website!
well the and the
so the only whole integers between them are 3,4,5,6. so there are 4 possible values
Answer by Alan3354(69443) (Show Source): You can put this solution on YOUR website!
square root(7)< x < square root(37)and x is an integer, then x can have how many different values?
----------------------
sqrt(7) = -2.645...
--> -2, -1, 0, 1, 2, 3, 4, 5, 6
= 9 integer values
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The final answer is: This is a poorly worded problem. The author did not take into account all the possibilities.
It's all too common. The people that write the textbooks don't go outside and have little contact with reality.
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