SOLUTION: 3a^2+a-10>0 we are using delta = b^2-4*a*c my solution to this equation is [-5/2,3} the book says the solution is (-oo,-2)U(5/3,oo) please help me find what I am doing wrong

SOLUTION: 3a^2+a-10>0 we are using delta = b^2-4ac my solution to this equation is [-5/2,3} the book says the solution is (-oo,-2)U(5/3,oo) please help me find what I am doing wrong

Question 264297: 3a^2+a-10>0
we are using delta = b^2-4*a*c
my solution to this equation is [-5/2,3} the book says the solution is (-oo,-2)U(5/3,oo)
please help me find what I am doing wrong

Answer by mananth(16946) (Show Source): You can put this solution on YOUR website!
3a^2+a-10>0
we are using delta = b^2-4*a*c
my solution to this equation is [-5/2,3} the book says the solution is (-oo,-2)U(5/3,oo)
please help me find what I am doing wrong
3a^2+a-10>0
3a^2+6a-5a-10>0
3a(a+2)-5(a+2)>0
(a+2)(3a-5)>0

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