SOLUTION: .6t+.2(t-8)< .5t- .6
Algebra.Com
Question 258763: .6t+.2(t-8)< .5t- .6
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
.6t+.2(t-8)< .5t- .6
Multiply thru both sides by 10 to get rid of the decimals.
----
6t + 2(t-8) < 5t - 6
---
6t + 2t - 16 < 5t - 6
8t - 16 < 5t -6
3t < 10
t < 10/3
===============
Cheers,
Stan H.
RELATED QUESTIONS
t(5t^2+6t) (answered by rfer)
5t-2(t+2)>8 (answered by Algebraic)
(-.5t) + 2 = (.2t) + .8
t =... (answered by rfer)
4(2-3t)+6t=-6t+8
8-12t+6t=-6t+8
8-12t=8
t=0
is this... (answered by rapaljer)
(6t+5t)=
(answered by Fombitz)
6t^2-5t+1 please factor... (answered by scott8148)
t^2-6t-27 (answered by algebrahouse.com)
I tried to complete but I got stuck
Perform the indicated operations
Probelm:... (answered by hellyeah)