SOLUTION: factor completely: 8x^4y^4-18x^2y^6

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Question 234171: factor completely:
8x^4y^4-18x^2y^6

Answer by Edwin McCravy(20086) About Me  (Show Source):
You can put this solution on YOUR website!
factor completely:
8x%5E4y%5E4-18x%5E2y%5E6

Look for the largest whole number you can factor out of 8 and 18.
This is 2.

Now look for the LARGEST power of x you can factor out.  This is
the SMALLEST power that occurs, but x must appear in ALL terms.
This is x%5E2


Now look for the LARGEST power of y you can factor out.  This is
the SMALLEST power that occurs, but y must appear in ALL terms.
This is y%5E4

So factor out 2x%5E2y%5E4

2x%5E2y%5E4%284x%5E2-9y%5E2%29

Now the expression in parentheses is the difference of two
perfect squares. 4x%5E2 is the same as %282x%29%5E2 and
9y%5E2 is the same as %283y%29%5E2 so that expression in
parentheses factors as the sum of times difference of the bases
of those perfect squares, i.e., their square roots:

2x%5E2y%5E4%282x-3y%29%282x%2B3y%29

Edwin