SOLUTION: Please help me solve. Thank you
(1-x)^2=9
I think that I am supposed to set it to zero but it somehow isn't working for me.
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Question 223590: Please help me solve. Thank you
(1-x)^2=9
I think that I am supposed to set it to zero but it somehow isn't working for me.
Found 2 solutions by checkley77, jsmallt9:
Answer by checkley77(12844) (Show Source): You can put this solution on YOUR website!
(1-x)^2=9
(1-x)=sqrt9
1-x=3
-x=3-1
-x=2
x=-2 ans.
Proof:
(1-(-2))^2=9
(1+2)^2=9
3^2=9
9=9
Answer by jsmallt9(3758) (Show Source): You can put this solution on YOUR website!
(Someone else's solution is only "half" of the answer. The error is that
not 1-x.)
Here's a few of ways to solve this: - Simple logic:
- The equation says that something squared equals nine.
- What numbers can be squared and result in a 9? Answer: 3 and -3.
- So (1-x) = 3 or (1-x) = -3. Now we just solve each equation:
1-x = 3 or 1-x = -3
-x = 2 or -x = -4
x = 2 or x = 4
- Clever use of the fact that and 9 are both perfect squares:
- Subtract 9 from each side:
- Factor as a difference of squares:
- Figure out what x values make the factors 0:
or
or
or
or
- Simplify and solve:
- Simplify the left side:
- Solve the equation. Since it is a quadratic equation we'll get one side equal to zero and then factor:
Now we'll figure out what x values make the factors zero:
or
or
Either way there are two solutions:
x = 4 or x = -2
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